12x^2-80x-400=0

Solution for 12x^2-80x-400=0 equation:

12x^2-80x-400=0

a = 12; b = -80; c = -400;
Δ = b2-4ac
Δ = -802-4·12·(-400)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-160}{2*12}=\frac{-80}{24}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+160}{2*12}=\frac{240}{24}
=10
$